What Am I?Math brain teasers require computations to solve.
I am a six digit number. My digits add up to 31, and all of my digits are distinct, and between 1 to 9 inclusive. All of my digits except one are odd. My second is 6 greater than my third, which is 5 less than my fifth. My last is 1 less than the previous digit, and the fourth is greater than the third. My first is equal to the sum of my fourth and fifth.
HintThe second and third numbers have to be 7 & 1.
AnswerThe second and third numbers have to be 7 & 1. The alternative 9 & 3 wouldn't work because that would make the fifth number 8 when the only even number is 6. The rest falls easily into place.
So I am 971365.
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