Empty the Reservoir
Math brain teasers require computations to solve.
A large fresh water reservoir has two types of drainage systems, small pipes and large pipes. 6 large pipes, on their own, can drain the reservoir in 12 hours. 3 large pipes and 9 small pipes, at the same time, can drain the reservoir in 8 hours. How long will 5 small pipes, on their own, take to drain the reservoir?
HintThe exact sizes of the pipes and reservoir do not matter.
21 hours and 36 minutes.
Dec 27, 2001
|I'm not quite sure how you arrived at this answer.|
Jun 11, 2002
|Here is the explanation. If 6 large pipes can drain it in 12 hours, then a single large pipe can drain it in 72 hours. In other words a large pipe drains 1/72 of the resevoir every hour. Additionally, in 8 hours, we are told, 9 small pipes and 3 large pipes can drain it. The three large pipes must have drained 24/72 of the resevoir( 8*3*(1/72)). Thus 9 small pipes must drain the remaining 48/72, or 2/3, of the resevoir in 8 hours. In other words a single small pipe can drain 2/3 in 72 hours. If a small pipe drains 2/3 in 72 hours, it drains the whole resevoir in 108 hours. We can now answer the question: 5 small pipes drain 5/108 of the resevoir each hour. It will therefore take 23.6 hours for the five pipes to drain the resevoir. |
Mar 05, 2006
Jun 18, 2006
|I'm going to assume that for the sake of your calculations, 23.6 = 21.6|
Jul 31, 2006
Feb 06, 2009
|Better than most of these type of teasers.|
Apr 15, 2009
|I just assumed that the reservoir contained 720 gigalitres and went from there (pick a number easily divisible by all of the 8s , 9s, etc). This tells you that a large pipe drains at a rate of 10 gigalitres per hour etc. Good teaser. |
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