Probability puzzles require you to weigh all the possibilities and pick the most likely outcome.
Jessica put six different colored beans in a bag. She had red, blue, pink, orange, yellow, and purple colored beans. There were 30 beans total in the bag. There were 4 red beans, 2 blue beans, 6 pink beans, 5 orange beans, 4 yellow beans, and 9 purple beans. What is the probability that someone could pull a pink or a yellow bean out of the bag?
You have a one third chance of getting a pink or a yellow bean.
10/30 = 1/3
Jun 13, 2006
|The answer is 33% or 1/3 because you add the pink and yellow together. You teh n get 10 out of 39 since 30 is the total. So your fraction is 10/30 so you reduce it and you get your answer which I already gave you at the top.|
Jun 13, 2006
|Duh, the answer basically says that, but whatever. That was pretty easy though. Just simple addition and reduction of fractions, easy peasy... |
Jun 15, 2006
|the prob you take pink beans is 6/30. the prob you take yellow beans is 4/30.|
so, the prob you take pink or yellow beans is: 6/30+4/30 = 10/30 = 1/3 (33.33..%)
Jun 17, 2006
|Easy, but cute. |
Jun 19, 2006
|I don't see the point of this teaser, the answer is clearly (6+4)/30=1/3.|
Not exactly a challenge unless you are a younger Braingler
Oct 14, 2006
|I'm truly perplexed. I knew the answer was either 1/3 or 100%... given the wording, the answer is 100%, and it should be in trick... given probability, it's 1/3. |
I wouldn't be so confused if the difficulty rating wasn't 1.78. I almost feel like I'm in the twilight zone??
This teaser should really be reworded, though. Because that chance that someone COULD pick a pink or yellow is 100%... anyone could do it, in theory... it should say "will" instead of "could." Also, the rest of the wording is somewhat ambiguous...
May 22, 2007
|Were they jelly beans? |
Dec 23, 2008
|Nothing said that person wasn't looking in the bag|
Jan 06, 2010
| a simple one but it rocks, horses_rock. hahahah!!! |
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