Anniversary Discount
Logic puzzles require you to think. You will have to be logical in your reasoning.
A fancy restaurant in New York was offering a promotional deal. A married couple could eat at the restaurant for half-price on their anniversary. To prevent scams, the couple would need proof of their wedding date.
One Thursday evening, a couple claimed it was their anniversary, but didn't bring any proof. The restaurant manager was called to speak with the couple. When the manager asked to hear about the wedding day, the wife replied with the following: "Oh, it was a wonderful Sunday afternoon, birds were chirping, and flowers were in full bloom." After nearly 10 minutes of ranting, she comes to tell him that today was their 28th wedding anniversary.
"How lovely", the manager said, "However, you do not qualify for the discount. Today is not your anniversary, you are a liar".
How did the manager know that it wasn't their anniversary?
Answer
The calendar repeats itself every 28 years. So, if they were married on a Sunday 28 years ago, the day they were at the restaurant would also have to be a Sunday. Since it was a Thursday, the manager knew they were lying, and abruptly kicked them out of his restaurant.
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Comments
blondebookworm   
Dec 02, 2006
| This is a really cool teaser, and I learned something new, which was fun. Great job Swaff!   |
1blessedgirl
Dec 02, 2006
| That was an easy one. But it was still a good one |
phrebh
Dec 04, 2006
| Good teaser, Swaff, but why did they get kicked out? Surely the manager would still like their money. |
bigSWAFF_69_
Dec 04, 2006
| Because they were really evil speghetti monsters. That wasn't included, because I doubt it would have been accepted with it. |
calmsavior
Dec 31, 2006
| I would just assume the restaurant owners were so PO'd at the fact a couple tried to scam them that they implemented their "refuse service to anyone" right. |
senther7
Jan 06, 2007
| Nice one |
vikingboy
Jan 06, 2007
| I'm thinking that maybe they divorced for a few years, then remarried. So, they are indeed celebrating their 28th year of being married, but the time from their first wedding day to now is more than 28 years.
Anyway, most restaurants run these types of gimmicks because they make more money on the wine anyway. Food is 50% off, but drinks are not. |
LeafFan4life
Feb 23, 2007
| well done you put alot of research into these young boy. might I add you have ALOT of time on ur hands to submit so many teasers |
natureluver 
Mar 21, 2007
|  I thought it was winter!!  |
Nicky101
Mar 26, 2007
| I didn't know the calendar repeats every 28 years. See, you can learn new things on spring break . Great teaser by the way. |
Jimbo
Mar 28, 2007
| Good one. Well researched. |
jin10doh
May 17, 2007
| Very good teaser.
It took some time to figure that one out.
Kudos! |
batatis
May 26, 2007
| or she might have been 28 years old...  |
soccerqueen1219
May 26, 2007
| i got this one!! |
(user deleted)
May 30, 2007
| im not sure that the 28 year thing is entirely accurate........my birthday tends to primarily fall on wednsdays and sundays, and its oct 29 which is not an irregular day by any means so i think it has to repeat more than that |
s_o_s
Jun 06, 2007
| Yes it definitely repeats more often than 28 years. I'm not 28 yet but have had birthdays on the same weekday that I was born! But this teaser still works, as 28 years would be the same weekday. |
taraskat
Jul 10, 2007
| Yes, a date may fall on the same day of the week every 5 or 6 years depending on the placement of leap years, but I'm guessing that every 28 years, all the dates and days of the week would be lined up exactly the same (i.e., both calendars exactly 28 years apart would either have leap day or not, which may or may not be the case when it's the same day of the week 5 or 6 years later).
I'm sure there's better mathematical reasoning behind it than I can summon at the moment, but the basic formula is 7 days of the week x 4 years in a leap-year cycle = 28 years.
Of course, what happens when it's the year 2100 and there's no leap day? (I think there's only a leap day on every fourth turn of the century -- i.e., 2000, 2400, 2800, etc.) Would the calendar repeat itself after 29 years in that case?  |
(user deleted)
Aug 14, 2007
| I am so glad that someone else caught the bit about leap year rules. I am really not sure about all the math here for a 28 year cycle... |
(user deleted)
Aug 14, 2007
| http://scienceworld.wolfram.com/
astronomy/JulianDate.html. The 28 year cycle would be for the Julian Calendar adapted in 46BC. Unfortunately this cycle became obsolete in the sense of this riddle in 1582 when the Gregorian calendar was succeeded the Julian Calendar. The same repetition in the days on the calendar is 400 years. |
_brynn
Sep 06, 2007
| oh haha, i guessed that it was winter...  |
FatHead
Sep 07, 2007
| Nice one! Easy, but still cool.
Taraskat, you are right about the century days, but it still works, because then, 28 years to the day after a particular Sunday would be a Saturday. (The proof is left to the reader.) |
Dragongenius
Dec 12, 2008
| um... are you counting leap years? I haven't done the math but it might work if you include leap years. I don't know |
javaguru
Jan 06, 2009
| Nice teaser. I was going to point out that even with the century rule, that the manager could eliminate 26 to 30 years. Also, presumably if the manager is smart enough to apply this rule, then he can also determine whether a non-leap-year century year occurred in the last 28 years. |
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