Candy
Logic puzzles require you to think. You will have to be logical in your reasoning.
A long time ago, candy was being sold at three prices: red candy at one for a penny, green candy at two for a penny, and blue candy at three for a penny. Some children (as many boys as girls) were given a total of seven pennies to spend on the candy. Each child received exactly the same value in candy. How many pieces of candy and what color candy did each child receive?
Answer
There must have been three boys and three girls, each of whom received two pieces of blue candy priced at three for a penny, and one piece of green candy priced at two for a penny. The total cost of the candy would be exactly 7 cents.
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Comments
puppybane
Oct 02, 2001
 Why could there not have been 1 boy, and
one girl, each getting 7 pieces of
green? 
(user deleted)
Nov 07, 2001
 or 7 boys and 7 girls each getting 1 piece of green 
dewtell
Aug 29, 2002
 Or 1 boy and 1 girl each getting 3.5 cents
worth of candy (several combinations, ranging from
3 reds and a green each to 7 greens each).

tissue
Sep 14, 2002
 @ran@ What is going on? 
tissue
Sep 14, 2002
 Why did it put @ran@ before my comment??? 
TehIgnored
Apr 18, 2006
 There are a multitude of possibilities to this teaser.... 
DEJL
Aug 23, 2006
 If I was them, I'd buy 7 red. 
scallio
Mar 13, 2007
 What exactly is the question for answering this teaser?
If the question is how many combinations of candy can be purchased then then there are 8... that means 4 boys and 4 girls.
7 red
1 green 5 red
2 green 3 red
3 green 1 red
1 blue 4 red
2 blue 3 red
1 blue 1 green 2 red
1 blue 2 green
This teaser needs some attending to. 
AlexRi3er
Jan 10, 2009
 How come there aren't 50 boys and 50 girls? How come there were 3 of each. This teaser needs some work, if it could somehow seggust that there were 6 children that would be good. 
makani
Aug 17, 2012
 Why should it matter what the genders of the kids are? 
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