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Logic puzzles require you to think. You will have to be logical in your reasoning.

 Puzzle ID: #8821 Fun: (2.8) Difficulty: (2.66) Category: Logic Submitted By: lesternoronha1

You are blindfolded before a table. On the table are a very large number of pennies. You are told 128 of the pennies are heads up and the rest are tails up. How can you create two subgroups of pennies, each with the same number of heads facing up, while remaining blindfolded?

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 OD-1 Dec 13, 2002 I DIDN'T GET IT A FIRST SO I TRYED IT WITH RANDOM #'S OF COINS .IT REALLY WORKS COOL TRICK. flynn Dec 31, 2002 Call me dumb, but I just can't get my head around this one. I used an example of a batch of 130 pennies; 128 heads and 2 tails. If I am blind folded and created a subgroup of another 128 pennies..surely they would be randomly heads and tails. I can't see how turning them over helps them match with the first set. sillywilly Jan 21, 2003 You're drawing 128 coins from the set of 130 you already have, not from a new pile of coins. You already know that 2 out of the 130 are tails. And there's nothing special about 128 - try the problem using 1 coin. Same logic.