The Secret Code
Math brain teasers require computations to solve.
A man wanted to get into his work building, but he had forgotten his code. However, he did remember five clues. These are what those clues were:
The fifth number plus the third number equals fourteen.
The fourth number is one more than the second number.
The first number is one less than twice the second number.
The second number plus the third number equals ten.
The sum of all five numbers is 30.
What were the five numbers and in what order?
Answer
7, 4, 6, 5, 8
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Comments
(user deleted)
Jan 20, 2004
 But he Could remember all of that? Weird guy... Nice teaser. 
Mamamunchies
Jan 20, 2004
 So, like what's the best way to figure this out? Or do I just try numbers until it works, which is what I did. I'm not strong on math... 
heyevpos
Jan 20, 2004
 Let O = digit 1, T = dig 2, R = dig 3, F = dig 4, V = dig 5.
O must be odd since 2*T0 = 1 (clue 3)
so, 0=1,3,5,7,9 which means T=1,2,3,4,5 (clue 3 again)
we know R+T = 10(clue 4) then R=9,8,7,6,5
we know FT = 1 (clue 2) then F=2,3,4,5,6
we know V+R = 14 (clue 1) then V=5,6,7,8,9
all of these possible values are listed respectively, so
our possible codes are
O T R F V
1 1 9 2 5 = 18
3 2 8 3 6 = 21
5 3 7 4 7 = 26
7 4 6 5 8 = 30 (clue 5)
9 5 5 6 9 = 34
7 4 6 5 8 is the solution

bbngk
Jan 20, 2004
 Difficult 
AXTON
Jan 21, 2004
 Why is this so Difficult. First I started by placing a nine in the fifth place. This resulting in a total sum of 34. So replaced the 9 with an 8 and got the correct answer. GREAT TEASER BUT IS NOT AS HARD AS IT IS MADE OUT TO BE!!! 
jo47
Jan 25, 2004
 I don't know if you purposefully left this out, but it would be easier if you said that no 2 numbers were the same. i enjoyed solving it anyway gj. 
jimbo
Feb 01, 2004
 Unnecessary information Jo. Taking the first clue, let 3rd number be x so 5th is 14x
From 4th clue 2nd is 10x.
This means the 4th number is 11x.
From the 3rd clue the first number is 192x.
Adding them 544x=30.
solving gives x = 6. Work backwards.
Nice puzzle! 
Nite_Owl
Feb 15, 2004
 Nice puzzle. Not too strong in difficulty but pretty good in fun. 
Candymn007
Feb 16, 2004
 Fun Teaser, not that hard. Just start with two digits equaling 14 and work your way back. 
tenzin_gyatsu
Feb 19, 2004
 I missed the boat on this one... I set N1+N2...+N5=30 and then put every number in terms of N2... this looked like (2N21)+N2+(10N2)+(N2+1)+[14(10N2)]=30. This puts N2=8 but then after substituting into the other equations I got a code of 15,8,2,9,12 which equals 46. I know this is way off but why can't I solve algebraically ?? Thanks 
(user deleted)
Mar 05, 2004
 I used the same method except that I got N2or B=4 and it all worked out.
(2B1)+B+(10B)+(B+1)+(4+B)=30
Jillian 
kittykat98
Oct 30, 2004
 it looked hard but turned out 2 b easy even though i didn't get it

Kollonel_Rabbit
Jan 11, 2005
 TOO EASY 
jacintan
Feb 21, 2005
 If u have trouble then talk 2 my maths teacher who goes onn and onn and onnnnnnnnn.....!!!!!!! 
(user deleted)
May 17, 2007
 x y z t e
9 3 7 4 7 
(user deleted)
May 17, 2007
 x y z t e
e+z=14
t=y+1
y+z=10
x+y+z+t+e=30
x+y+10y+y+1+4+y=30
x+2y= 15
x must be 2
e=4+y
e must be 
javaguru
Jan 03, 2009
 I've got to agree with the too easy, but I guess they don't all need to be hard. Simple algebra problem without any twists. 
(user deleted)
Jul 26, 2009
 The problem is wronge.... Take the answer from the computer and pug them into the clues they do not match.... So all you people who think your smart...CHECK YOUR WORK!!!!!!!!!!!!!! 
(user deleted)
Sep 18, 2009
 Nice one;
I think it is easy to remember the five digit code than those clues. 
(user deleted)
Nov 19, 2010
 How the hell can he remember all these gay clues but not remember the god damn code!!! 
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