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## Shoe Available

Logic Grid puzzles come with a handy interactive grid that will help you solve the puzzle based on the given clues.

 Puzzle ID: #34877 Fun: (2.72) Difficulty: (3.01) Category: Logic-Grid Submitted By: Gizzer Corrected By: MarcM1098

The old woman who lives in a shoe has finally reached mandatory retirement age, and Mother Goose is now interviewing possible replacements. None of the five applicants is currently living in a shoe, though each notes on his or her application that he or she is living in a different eccentric domicile. And, although none has children, each applicant shares his or her abode with a number of domestic animals. No two keep the same type of animal.

While Mother Goose checks with her personnel department, see if you can match each applicant up with his or her domicile, as well as with the number and type of domestic animals each owns.

Names: Fanny, Gladys, Horace, Inez, Joe
Domiciles: banjo, churn, gourd, hat, jukebox
Animals: cats, chickens, geese, pigs, sheep
Numbers: not provided - you have to figure them out!

TBD (in the grid) = to be determined
Clues:

1. Two applicants have the same number of animals, while each of the others has a different number.

2. The one who keeps geese lives in a jukebox.

3. Joe shares his abode with chickens.

4. The one who lives in a gourd has four fewer animals than Gladys (who doesn't raise sheep).

5. Fanny has 15 animals, which isn't the lowest number.

6. The one who shares his or her domicile with 19 sheep (who doesn't live in the churn) doesn't have the most animals.

7. The one who keeps cats doesn't have the lowest number of animals, but he or she does have three fewer animals than the applicant who lives in a banjo.

8. Inez (who doesn't live in a hat) has three fewer animals than another applicant.

Fanny lives in a gourd with 15 pigs.
Gladys lives in a churn with 19 cats.
Horace lives in a hat with 19 sheep.
Inez lives in a jukebox with 12 geese.
Joe lives in a banjo with 22 chickens.

Explanation:

Someone has fewer than 15 animals (clue 5), and someone has more than 19 animals (clue 6). Therefore, the four unique numbers of animals are: the least, 15, 19 and the most. The fifth number matches one of these (clue 1).

The number of cats is neither the least nor the most, nor can there be 15 cats, as then someone would have 18 animals, which isn't possible. Therefore, there are 19 cats, and the "most" animals is 22 (clue 7). There are also 19 sheep (clue 6), so the numbers of animals are: the least, 15, 19, 19 and 22.

Gladys can't have the least animals, or the most (22), as then someone would have to have 18 animals (clue 4). Since Fanny has 15 animals, Gladys must have 19, and since she doesn't have sheep (clue 4), she has the 19 cats. This means that Fanny lives in the gourd (clue 4). She doesn't keep chickens (clue 3) or geese (clue 2), so Fanny has 15 pigs. The geese live in the jukebox, therefore Joe must live in the banjo with his 22 chickens (clues 3 and 7).

The sheep don't live in the churn (clue 6), so they live in the hat, and the cats live in the churn. (Remember, "The Cat in the Hat" is Dr. Seuss, not Mother Goose!)

Inez doesn't live in the hat, so Horace does, while Inez lives in the jukebox with her 12 geese (clue 8).

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