Terminate AverageMath brain teasers require computations to solve.
There is a scoring system in which the highest is 4, and the lowest is 1, and you may only vote whole numbers.
Imagine that six people voted before you, and they all voted the same thing, however you do not know what they rated. You vote seventh, and your two friends behind you would vote whatever you did.
If you are the one in the end tallying the scores, and you want the average to be a simple, terminating decimal number, what would your best bet to vote for be?
AnswerThe format of the answers will be...
[Previous 6], [Your Choice], [Average of all 9]
1, 1, 1
1, 2, 1.3(cont)
1, 3, 1.6(cont)
1, 4, 2
2, 1, 1.6(cont)
2, 2, 2
2, 3, 2.3(cont)
2, 4, 2.6(cont)
3, 1, 2.3(cont)
3, 2, 2.6(cont)
3, 3, 3
3, 4, 3.3(cont)
4, 1, 3
4, 2, 3.3(cont)
4, 3, 3.6(cont)
4, 4, 4
If you choose 1, then you have a 2/4 chance of having a terminating end average.
If you choose 2, then you will have a 1/4 chance of having a terminating average.
If you choose 3, then you will have a 1/4 chance of having a terminating average.
If you choose 4, then you will have a 2/4 chance of having a terminating average.
Your best bets are choosing 1 or 4. Now, you can still vote based on whether you liked it or not. If you did, then you choose 4. If you didn't, choose 1. If you choose 1 or 4, it won't have a difference on whether the average is terminating or not.
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