Brain Teasers
Brain Teasers Trivia Mentalrobics Games Community
Personal Links
Submit a Teaser
Your Favorites
Your Watchlist
Browse Teasers
All

Cryptography
Group
Language
Letter-Equations
Logic
Logic-Grid
Math
Mystery
Optical-Illusions
Other
Probability
Rebus
Riddle
Science
Series
Situation
Trick
Trivia

Random
Daily Teasers
Search Teasers

Advanced Search
Add to Google Add to del.icio.us

More ways to get Braingle...

Tic Tac Toe

Math brain teasers require computations to solve.

 

Puzzle ID:#5388
Fun:*** (2.81)
Difficulty:** (1.62)
Category:Math
Submitted By:im_para_noid*****

 

 

 



Arrange the numbers 1 through 9 on a tic tac toe board such that the numbers in each row, column, and diagonal add up to 15.

Open Calculator

Answer

4, 3, 8,
9, 5, 1,
2, 7, 6,

Hide




What Next?

  
  

See another brain teaser just like this one...

Or, just get a random brain teaser

If you become a registered user you can vote on this brain teaser, keep track of
which ones you have seen, and even make your own.

 



Comments

dsquared*nz*
Jul 22, 2002

Nice one... many possible scramblings of the answer too ;P
xiaobaby
Aug 10, 2002

rather simple.. just have 2,4,6 and 8 anywhere at the corners and 5 in the middle and u can easily solve it
sillywilly
Aug 10, 2002

This one was really fun because there are so many ways to solve it, and many ways to get the "aha!" - you can check for the center (same number, 4 combos - only 5 works), or do the big numbers (987 need to be on different rows/columns and not on a diag) - on and on. very good fun.
pemalova
Aug 21, 2002

I got that in like 5 minutes. Is that good? Dang. I sound like a girl. Oh well....there's nothing wrong with being in touch with my feminine side is there?
SgtScoobz
Apr 05, 2003

a little easy for my tastes because we do that stuff in math all of the time
gcriotgurl
Aug 10, 2003

this was pretty boring...sorry but it was. i've had to do this i don't know how many times in school so far for EXTRA CREDIT...pretty lame.
luvupurpleA*
Aug 10, 2003

GOOD 1! -luvupurple
JmBannana*
Aug 11, 2004

I also have to say it was pretty easy but a good teaser
Skybet*gb*
Nov 20, 2004

Takes prettly long to work out, but time consuming and fun, good job
deadeye823**
Apr 10, 2005

ive done this before, you can even do boxes of four by four but i forget what they have to add up to...
lilredc5*
Jun 06, 2007

Hmm.. Answer maybe should have indicated that there are several other answers, and maybe some reasoning behind it. The people that said it is easy say that because they got lucky in their trial-and-error. No one mentioned any logic, like 1 can't go with 2 or 3, 7 can't go with 4, 9 can't go with 3 or 6-8, and that 5 is the only number w/o any restrictions and thusly must go in the middle, since every other square forms a sum somehow with the middle square.
pating**
Aug 31, 2007

I was told of the solution to this problem before when I was a child. But it only works if the box is an odd number, meaning its 3x3, 5x5, 7x7, etc...

Firstly, you can draw a grid, say 5x5 grid.

Then place the 1 in the right-most column, middle row.
Next step is, go 1 box down, 1 box to right, then you place the next number (2) in that box.
But if you're on the right-most column, and you need to go 1 box to the right, you'll have to go 4 boxes to left instead (or go to the left-most box in the same row).
And if you need to go 1 box below and you're in the bottom row, you'll have to go 4 boxes above instead (or go to the top-most box in the same column).

You'll notice that if you're already in the number 5, if you go 1 box down and 1 box to right, that box is already occupied by number 1. So instead, go 1 box to left and place the next number (6) there. Then repeat the process.

Here is the solution for a 5x5 grid.

11 10 4 23 17
18 12 6 5 24
25 19 13 7 1
2 21 20 14 8
9 3 22 16 15

The sums of the columns, rows and diagonal are all 65.
You can try it in a 7x7 grid, the sums should be 175!
pating**
Aug 31, 2007

11_10__4_23_17
18_12__6__5_24
25_19_13__7__1
_2_21_20_14__8
_9__3_22_16_15
javaguru*us*
Jan 04, 2009

Very nice solution pating. I think I saw that before, but had forgotten about it.

The sum for each row/column/diagonal in an NxN magic square is (NxN+1) x N/2.
opqpop
Sep 10, 2010

The middle number requires 4 sets of pairs with equal sum. Hence, 5 is the only possible middle number. From there, it's casework with 9-1 being a sum in a diagonal or non-diagonal. Use the 9 to figure out where 8 can go, and you eventually arrive at the only case that works.



Back to Top
   



Users in Chat : cooltigerr1 

Online Now: 9 users and 397 guests

Copyright © 1999-2014 | Updates | FAQ | RSS | Widgets | Links | Green | Subscribe | Contact | Privacy | Conditions | Advertise

Custom Search





Sign In A Create a free account