|
| Posted by Phyllis | 02/01/01 |
| What is a rooth? |
|
| Posted by thephirm | 10/18/01 |
| Your claim that taking the positive root of any negative number results in an imaginary number is incorrect. For example, the cube root of -1 is -1 (-1 * -1 * -1 = -1). However the even root of any negative number will be imaginary. |
|
| Posted by canu | 07/13/04 |
| The words in the teaser look like English words, but put together they have no meaning in English or in math. |
|
| Posted by Sane | 03/20/05 |
| I did the subtraction wrong and came out with:
1/100 000 000
0.00000001
:D |
|
| Posted by darthforman | 05/25/05 |
| :-? |
|
| Posted by stephiesd | 12/09/05 |
| i read it wrond after i did the subtraction, i read it as the -8th power, resulting in -1.
anyhow, we haven't covered imaginary numbers yet. i think they're next chapter. |
|
| Posted by mr_brainiac | 01/11/06 |
| I don't think that the answer is really an imaginary number, I think it's more likely an imaginary imaginary number, or maybe it's an imaginary imaginary imaginary number, or maybe it's ... |
|
| Posted by lessthanjake789 | 01/29/06 |
| wrong... all of you. the number t is a positive, real number. let t = 100, t+1 = 101. t-(t+1) = -1, raised to the 1/8th is, truly an imaginary number, but as you can see, "t" is ANY real number, positive or negative. sorry, but poorly thought out teaser |
|
| Posted by Methlos | 03/12/06 |
| I thing i might put my head under a pillow for a while |
|
| Posted by Brainy_1 | 03/18/06 |
| :o That hurt my head! Nice job though! 8) |
|
| Posted by MadDog72 | 03/23/06 |
| I see four problems with this teaser:
1) It asks for the number t, not the value of (t-(t+1))^(1/8).
2) Why bother with t? Isn't it obvious that if t+1 is subtracted from t, the result is -1?
3) The answer is vague. I actually computed the answer, only to find that all you wanted was 'imaginary'.
4) It's not an imaginary number! An imaginary number is a number of the form b*i, where i^2=-1. The answer is of the form a + b*i, where a is nonzero (there are actually 8 answers, but they are all of this form). The answer is complex and not real, but not imaginary either. |
|
| Posted by Krystle | 07/23/06 |
| wow, i'm not good at math at all :( |
|
| Posted by Qrystal | 07/29/06 |
| I figured that a mathematician would call 't' TRIVIAL. After all, it got subtracted out of the situation right away.
There must be a way this teaser could be improved so that it asks what it means to ask... although of course MadDog72 is absolutely correct in stating that [-1]^[1/8] is technically considered complex, not imaginary.
Does anyone care that [-1]^[1/8] has 8 answers? :P
Let A = cos(pi/8). Let B = sin(pi/8).
Then [-1]^[1/8] =
( A + B*i, B + A*i, -B + A*i, -A + B*i,
-A - B*i, -B - A*i, B - A*i, A - B*i )
Anyways, I don't care if anyone else doesn't care; I wrote it because I care. So there. |
|
| Posted by Qrystal | 07/29/06 |
| eeek my answer got invaded by sunglass dudes!
That should say:
Let A = cos[pi/8]. Let B = sin[pi/8]. |
|
| Posted by dimez_00 | 10/22/06 |
| i figured this:
(t+1)-t=? ?^1/8 therefore i got
t+1-t=1 1^1/8=the 8th root of 1 which is 1 |
|
| Posted by ChristheGreat | 11/12/06 |
| Hmm.. you did't include the fact that pi to the 3rd power minus the radius of a duck's butt plus the deepness of a toilet = 5 times the 3rd trigonometric function plus the amount of time it takes for the final star to impact the earth causing free cake for everyone! :lol: :lol: :lol: |
|
| Posted by EA_KLEIN | 03/15/07 |
| whoever wrote this has some loose marbles in his keppie |
|
| Posted by jamesbond | 04/19/07 |
| ya ryt |
|
| Posted by SRB_1807 | 08/17/11 |
| I love 2 eat ducks.. :lol: :lol: :lol: :lol: |
