Braingle Lite



Formula

Category:Math
Submitted By:DakarMorad
Fun:** (1.84)
Difficulty:**** (3.35)



If you use a certain formula on 13, you end up with 7.

Under the same formula, 2352 becomes 16, 246 becomes 14, 700 turns into 16, and 1030 becomes 14.

What would 9304 become?

Show Answer



Comments on this teaser


Posted by I_am_the_Omega01/08/05
Doesn't 9304 convert to 00111001 00110011 00110000 00110100? ...

Posted by DakarMorad01/09/05
Omega: 9304 is 8192 + 1024 + 64 + 16 + 8. Orange: Well, your a first. ;) Sorry that this teaser was so difficult. It's my first.

Posted by saucyangel01/10/05
ok, i NEVER would have figured that out! (well, maybe after i sat there and thought about it for an hour or three...) good one! :P

Posted by cloud_strife01/18/05
err... what is a binary??

Posted by Atropus01/18/05
Odd.. I guessed it had to do with binary.. but it was really just too obscure. For your next one perhaps you chould add a hint ^_^

Posted by God-sGrace200501/23/05
:-? :-? :-? I don\'t get it and what is binary?

Posted by DakarMorad01/24/05
Atropus: I\'ll keep that in mind. Binary is a system of counting that uses only 1s and 0s instead of 1-9 as digits. 1 is one, 10 is two, 11 is three, 100 is four, etc.

Posted by CPlusPlusMan01/30/05
I wouldn't necessarily call a binary conversion a formula, but great teaser anyways! When I saw it wasn't a function, it had me really thrown off. I'd never of even guessed of binary!

Posted by Gandalf02/14/05
it was hard but when my sister got it i felt so embarresed evn though shes older then me

Posted by sftbaltwty02/17/05
haha..i always knew there was reason i stopped taking math and stuck to english........ :wink:

Posted by waffle02/27/05
How were we ever supposed to arive at that answer? :-?

Posted by ben204/07/05
great one :D

Posted by sweetime05/16/05
i know what binary is, but have never used it in my whole life. how does 10010001011000 = 19?

Posted by darthforman05/22/05
:-? :-? :-? :oops: :cry: :x :oops:

Posted by solidtanker06/10/05
These kinds of puzzles are not my favorite because anyone can come up with an arbitrary system to convert one number into another. There are infinite ways to do so.

Posted by rashad06/11/05
I feel so jealous because some of you understood it and I didn't get a single atom of it!!! :o :x

Posted by schatzy22808/27/05
great teaser,,those who didnt like it just dont get the concept of "teaser",,,,but its all good 8)

Posted by soccercow1008/29/05
HuH!?!?!? :oops: that was a fun teaser to try and find out !! even though i didnt :oops: all i have to say is creative.....creative indeed

Posted by i_am_hated09/28/05
:o !!!

Posted by usaswim10/28/05
:o :o :o :o :o :o :o :o :o :o

Posted by mrbrainyboy11/18/05
:o :o :o The hardest teaser in the whole site... wow :o 8)

Posted by lovefrenzy11/30/05
what :-?

Posted by qqqq12/20/05
My head hurts. :o

Posted by teen_wiz02/09/06
Ow. :o My brain is killing me. :lol:

Posted by coolblue05/21/06
So many zeroes, and who the heck heard of the binary system? :P :P

Posted by sftball_rocks1306/14/06
huh.......

Posted by soccercow1011/20/06
can someone please explain this to me? lol sorry too hard

Posted by sftball_rocks1302/27/07
Um... :D My brain hurts :o but this was pretty good, I learned binary in school this year, but I would have NEVER gotten that :D good teaser!

Posted by MrDoug03/18/07
I don't like this one because it doesn't have a clear (single) correct answer. There are lots of formulas that give the given numbers. For example, one can construct (as already stated) a 4th-degree polynomial which takes on all the valued specified (or infinitely many polynomials of degree 5 or higher), and any of these qualify as a "formula." It might help to give some clue as to what you had in mind, such as "The formula I have in mind only applies to integers, and it always gives an integer value." This at least rules out continuous mathematics and identifies it as a discrete problem, which is apparently what you intended.

Posted by brainglewashed06/14/07
DANG I SAID 1,000,000,000 :oops: :oops: :-? :-? :-? :D :D

Posted by Pojuer06/28/07
too hard :o

Posted by Brainyday11/11/07
I am confused. :-? :-? :-? :-? :-?

Posted by UlsterCharlotte01/14/08
I agree with MrDoug. This is WAY too obscure. You realize right away that there are multiple answers. Not good at all. Who proofreads/screens these things anyway?

Posted by annvie903/30/08
I would only get this answer if I sat there for a whole day. But if I did, I would staring at the ceiling doing nothing anyways. :D

Posted by Natrix05/14/08
If you want people to understand this add a hint that says "This number willbe converted into binary."

Posted by EvilMonkeySpy312/02/08
darrhhhhhararrrrrrr...... :o i'm only in seventh grade.... :( i had absolutely no idea..... XP

Posted by piratechicken9212/04/08
that was waaaaay to hard for me2 :oops:

Posted by javaguru12/10/08
Lame. As mentioned before, arbitrarily obscure without a unique or obviously correct answer. And to greenrazi: You're are probably thinking of hexadecimal (base 16), where each digit can have one of 16 values. A binary representation of a hexadecimal number would have a granularity of 4 bits.

Posted by rashad05/07/09
Wonderful,yet ...impossible.

Posted by xandrani01/21/10
There is more than one solution. The binary answer is more succinct and sweeter therefore it is the 'official' answer, but this also works: a = 0.00000000003090981409468774 b = -0.000000087318835992468036 c = 0.000023696152096488413 d = 0.028997981886427873 e = 6.6192125424396062 f(x) = a(x^4) + b(x^3) + c(x^2) + dx + e So answer would be: f(9304) = 163621

Posted by xandrani01/23/10
Note that the above function should strictly have read: f(x) = floor(a(x^4) + b(x^3) + c(x^2) + dx + e) Where floor rounds down to the nearest integer. Note that this can also be written as: f(x) = ⎣a(x^4) + b(x^3) + c(x^2) + dx + e⎦ See: http://mathworld.wolfram.com/CeilingFunction.html

Posted by xandrani01/23/10
I have noticed a few comments stating that the answer is not a function... however aside from the function above I posted (which is one solution), I now also post another function which fits the other solution. Almost anything can be made in to a function. g(x) = 1 + g(x - 2^⎣logx/log2⎦) Where x ≠ 0 and g(0) = 0 f(x) = 1 + ⎣logx/log2⎦ + g(x) Let's try and solve for x = 9304: f(9304) = 1 + 13 + g(9304) g(9304) = 1 + g(9304 - 2^13) = 1 + g(1112) g(1112) = 1 + g(1112 - 2^10) = 1 + g(88) g(88) = 1 + g(88 - 2^6) = 1 + g(24) g(24) = 1 + g(24 - 2^4) = 1 + g(8) g(8) = 1 + g(8 - 2^3) = 1 + g(0) = 1 So iterating out we get: 9(24) = 1 + 1 = 2 9(88) = 1 + 2 = 3 9(1112) = 1 + 3 = 4 g(9304) = 1 + 4 = 5 So therefore: f(9304) = 1 + 13 + 5 = 19

Posted by xandrani01/23/10
The smiley faces with glasses should be '8 )'.

Posted by xandrani01/23/10
I have noticed a few comments stating that the answer is not a function... however aside from the function above I posted (which is one solution), I now also post another function which fits the other solution. Almost anything can be made in to a function. g(x) = 1 + g(x - 2^⎣logx/log2⎦) Where x ≠ 0 and g(0) = 0 f(x) = 1 + ⎣logx/log2⎦ + g(x) Let's try and solve for x = 9304: f(9304) = 1 + 13 + g(9304) g(9304) = 1 + g(9304 - 2^13) = 1 + g(1112) g(1112) = 1 + g(1112 - 2^10) = 1 + g(8 ) g(8 ) = 1 + g(88 - 2^6) = 1 + g(24) g(24) = 1 + g(24 - 2^4) = 1 + g(8 ) g(8 ) = 1 + g(8 - 2^3) = 1 + g(0) = 1 So iterating out we get: 9(24) = 1 + 1 = 2 9(8 ) = 1 + 2 = 3 9(1112) = 1 + 3 = 4 g(9304) = 1 + 4 = 5 So therefore: f(9304) = 1 + 13 + 5 = 19

Posted by xandrani01/23/10
Damn smilies! I post yet again: I have noticed a few comments stating that the answer is not a function... however aside from the function above I posted (which is one solution), I now also post another function which fits the other solution. Almost anything can be made in to a function. g(x) = 1 + g(x - 2^⎣logx/log2⎦) Where x ≠ 0 and g(0) = 0 f(x) = 1 + ⎣logx/log2⎦ + g(x) Let's try and solve for x = 9304: f(9304) = 1 + 13 + g(9304) g(9304) = 1 + g(9304 - 2^13) = 1 + g(1112) g(1112) = 1 + g(1112 - 2^10) = 1 + g(88 ) g(88 ) = 1 + g(88 - 2^6) = 1 + g(24) g(24) = 1 + g(24 - 2^4) = 1 + g(8 ) g(8 ) = 1 + g(8 - 2^3) = 1 + g(0) = 1 So iterating out we get: 9(24) = 1 + 1 = 2 9(88 ) = 1 + 2 = 3 9(1112) = 1 + 3 = 4 g(9304) = 1 + 4 = 5 So therefore: f(9304) = 1 + 13 + 5 = 19

Posted by xandrani01/23/10
There are indeed many solutions to this one, here's another just for fun: n = floor(x / 230) f(x) = 14 - 7(x mod 2) + (1 - (x mod 2))((n^2 - n) mod 4) f(9304) = 14




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