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Who Am I?

Category:Math
Submitted By:cacmjc
Fun:*** (2.13)
Difficulty:* (0.95)



I am a two-digit number. The sum of my digits is 11. I am divisible by both 4 and 7. What number am I?

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Comments on this teaser


Posted by Brainiac2309/01/08
wow....

Posted by megabreath09/01/08
Very, very easy. But still good fun. :D

Posted by Just_Jenn09/02/08
I am not sure how you are *supposed* to go about solving this... I just 4*7 (28 which does NOT equal 11) then multiplied that by 2 to get 56.... figured it anyways ;)

Posted by cm_mcginty09/04/08
too easy, 7 being a prime number means that it has to be a multiple of 7 x 4 (28) and there are only 3 options with 2 digits

Posted by cm_mcginty09/04/08
not meant to be 8) btw, meant to be 8 ) without the space

Posted by stil09/14/08
4 * 7 fully factored is 2 * 2 * 7. To arrive at an acceptable answer, one need only test numbers which add additional factors of 2 or 7. Also note- the sum being 11, possibilities are limited to the set, {29, 38, 47, 56, 65, 74, 83, 92}.

Posted by Malika12311/27/08
Fun & easy.




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