Lite |

Category: | Series |

Submitted By: | shenqiang |

Fun: | (1.8) |

Difficulty: | (3.11) |

0, 1, 1, 3, 1, 6, 1, 7, 4, 8, ?, ?, ?

Show Hint | Show Answer |

Posted by tpg76 | 09/14/08 |

I think the primes should be 2, not 1 - the divisors are 1 and the number itself. In any event it is not consistent to list the number of divisors for entry 4 as "3", because that would have to include 1, 2, and 4 - i.e., the number itself. Thus for consistency, the primes should all be listed as "2". | |

Posted by tpg76 | 09/14/08 |

Never mind - I reread your wording and understand my mistake now. "Sum" of the divisors - you are correct, as usual! | |

Posted by markmonnin | 09/15/08 |

Neat. I couldn't figure this one out. :) |

Most Popular | Hardest | Easiest