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Category: | Logic |

Submitted By: | cnmne |

Fun: | (2.28) |

Difficulty: | (3.21) |

There is a ten-digit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?

1) Either A = B / 3 or A = G + 3.

2) Either B = I - 4 or B = E + 4.

3) Either C = J + 2 or C = F * 3.

4) Either D = G * 4 or D = E / 3.

5) Either E = J - 1 or E = D / 4.

6) Either F = B * 2 or F = A - 4.

7) Either G = F + 1 or G = I - 3.

8) Either H = A / 2 or H = C * 3.

9) Either I = H + 3 or I = D / 2.

10) Either J = H - 2 or J = C * 2.

Show Answer |

Posted by jhosek | 11/24/10 |

I got it. A little tricky but solvable. | |

Posted by quesadillaman12 | 01/09/11 |

My brain hurts. :-? | |

Posted by affanak | 05/10/11 |

Equation 1. A= B/3 From your solution: B=0, which would imply that A=0 too. 0/3=3 | |

Posted by affanak | 05/10/11 |

Take back my comment (cant delete it) | |

Posted by galanix | 02/03/12 |

Good puzzle. I followed a strategy similar to the one you displayed in the answer but slightly different. After a few passes instead of testing the different values of D I just tested which letter could be 0. At that point I had B,E,F, and J which could possibly be 0. I tried B as zero first and it worked. | |

Posted by galanix | 02/03/12 |

Simplified version of the answer: A = G + 3 = 5 B = I - 4 = 0 C = F * 3 = 3 D = G * 4 = 8 E = J - 1 = 6 F = A - 4 = 1 G = F + 1 = 2 H = C * 3 = 9 I = D / 2 = 4 J = H - 2 = 7 |

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