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| Posted by I_am_the_Omega | 01/08/05 |
| Doesn't 9304 convert to 00111001 00110011 00110000 00110100? ... |
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| Posted by DakarMorad | 01/09/05 |
| Omega: 9304 is 8192 + 1024 + 64 + 16 + 8.
Orange: Well, your a first. ;)
Sorry that this teaser was so difficult. It's my first. |
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| Posted by saucyangel | 01/10/05 |
| ok, i NEVER would have figured that out! (well, maybe after i sat there and thought about it for an hour or three...) good one! :P |
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| Posted by cloud_strife | 01/18/05 |
| err... what is a binary?? |
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| Posted by Atropus | 01/18/05 |
| Odd.. I guessed it had to do with binary.. but it was really just too obscure.
For your next one perhaps you chould add a hint ^_^ |
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| Posted by God-sGrace2005 | 01/23/05 |
| :-? :-? :-? I don\'t get it and what is binary? |
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| Posted by DakarMorad | 01/24/05 |
| Atropus: I\'ll keep that in mind.
Binary is a system of counting that uses only 1s and 0s instead of 1-9 as digits.
1 is one,
10 is two,
11 is three,
100 is four,
etc. |
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| Posted by CPlusPlusMan | 01/30/05 |
| I wouldn't necessarily call a binary conversion a formula, but great teaser anyways! When I saw it wasn't a function, it had me really thrown off. I'd never of even guessed of binary! |
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| Posted by Gandalf | 02/14/05 |
| it was hard but when my sister got it i felt so embarresed evn though shes older then me |
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| Posted by sftbaltwty | 02/17/05 |
| haha..i always knew there was reason i stopped taking math and stuck to english........ :wink: |
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| Posted by waffle | 02/27/05 |
| How were we ever supposed to arive at that answer? :-? |
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| Posted by ben2 | 04/07/05 |
| great one :D |
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| Posted by sweetime | 05/16/05 |
| i know what binary is, but have never used it in my whole life.
how does 10010001011000 = 19? |
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| Posted by darthforman | 05/22/05 |
| :-? :-? :-? :oops: :cry: :x :oops: |
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| Posted by solidtanker | 06/10/05 |
| These kinds of puzzles are not my favorite because anyone can come up with an arbitrary system to convert one number into another. There are infinite ways to do so. |
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| Posted by rashad | 06/11/05 |
| I feel so jealous because some of you understood it and I didn't get a single atom of it!!! :o :x |
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| Posted by schatzy228 | 08/27/05 |
| great teaser,,those who didnt like it just dont get the concept of "teaser",,,,but its all good 8) |
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| Posted by soccercow10 | 08/29/05 |
| HuH!?!?!? :oops:
that was a fun teaser to try and find out !!
even though i didnt :oops:
all i have to say is creative.....creative indeed |
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| Posted by i_am_hated | 09/28/05 |
| :o
!!! |
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| Posted by usaswim | 10/28/05 |
| :o :o :o :o :o :o :o :o :o :o |
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| Posted by mrbrainyboy | 11/18/05 |
| :o :o :o
The hardest teaser in the whole site...
wow :o 8) |
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| Posted by lovefrenzy | 11/30/05 |
| what :-? |
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| Posted by qqqq | 12/20/05 |
| My head hurts. :o |
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| Posted by teen_wiz | 02/09/06 |
| Ow. :o My brain is killing me. :lol: |
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| Posted by coolblue | 05/21/06 |
| So many zeroes, and who the heck heard of the binary system? :P :P |
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| Posted by sftball_rocks13 | 06/14/06 |
| huh....... |
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| Posted by soccercow10 | 11/20/06 |
| can someone please explain this to me? lol sorry too hard |
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| Posted by sftball_rocks13 | 02/27/07 |
| Um... :D My brain hurts :o but this was pretty good, I learned binary in school this year, but I would have NEVER gotten that :D good teaser! |
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| Posted by MrDoug | 03/18/07 |
| I don't like this one because it doesn't have a clear (single) correct answer. There are lots of formulas that give the given numbers. For example, one can construct (as already stated) a 4th-degree polynomial which takes on all the valued specified (or infinitely many polynomials of degree 5 or higher), and any of these qualify as a "formula."
It might help to give some clue as to what you had in mind, such as "The formula I have in mind only applies to integers, and it always gives an integer value." This at least rules out continuous mathematics and identifies it as a discrete problem, which is apparently what you intended. |
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| Posted by brainglewashed | 06/14/07 |
| DANG I SAID 1,000,000,000 :oops: :oops: :-? :-? :-? :D :D |
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| Posted by Pojuer | 06/28/07 |
| too hard :o |
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| Posted by Brainyday | 11/11/07 |
| I am confused. :-? :-? :-? :-? :-? |
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| Posted by UlsterCharlotte | 01/14/08 |
| I agree with MrDoug. This is WAY too obscure. You realize right away that there are multiple answers. Not good at all. Who proofreads/screens these things anyway? |
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| Posted by annvie9 | 03/30/08 |
| I would only get this answer if I sat there for a whole day. But if I did, I would staring at the ceiling doing nothing anyways. :D |
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| Posted by Natrix | 05/14/08 |
| If you want people to understand this add a hint that says "This number willbe converted into binary." |
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| Posted by EvilMonkeySpy3 | 12/02/08 |
| darrhhhhhararrrrrrr...... :o i'm only in seventh grade.... :( i had absolutely no idea..... XP |
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| Posted by piratechicken92 | 12/04/08 |
| that was waaaaay to hard for me2 :oops: |
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| Posted by javaguru | 12/10/08 |
| Lame. As mentioned before, arbitrarily obscure without a unique or obviously correct answer.
And to greenrazi: You're are probably thinking of hexadecimal (base 16), where each digit can have one of 16 values. A binary representation of a hexadecimal number would have a granularity of 4 bits. |
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| Posted by rashad | 05/07/09 |
| Wonderful,yet ...impossible. |
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| Posted by xandrani | 01/21/10 |
| There is more than one solution. The binary answer is more succinct and sweeter therefore it is the 'official' answer, but this also works:
a = 0.00000000003090981409468774
b = -0.000000087318835992468036
c = 0.000023696152096488413
d = 0.028997981886427873
e = 6.6192125424396062
f(x) = a(x^4) + b(x^3) + c(x^2) + dx + e
So answer would be:
f(9304) = 163621 |
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| Posted by xandrani | 01/23/10 |
| Note that the above function should strictly have read:
f(x) = floor(a(x^4) + b(x^3) + c(x^2) + dx + e)
Where floor rounds down to the nearest integer.
Note that this can also be written as:
f(x) = ⎣a(x^4) + b(x^3) + c(x^2) + dx + e⎦
See:
http://mathworld.wolfram.com/CeilingFunction.html |
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| Posted by xandrani | 01/23/10 |
| I have noticed a few comments stating that the answer is not a function... however aside from the function above I posted (which is one solution), I now also post another function which fits the other solution. Almost anything can be made in to a function.
g(x) = 1 + g(x - 2^⎣logx/log2⎦)
Where x ≠0 and g(0) = 0
f(x) = 1 + ⎣logx/log2⎦ + g(x)
Let's try and solve for x = 9304:
f(9304) = 1 + 13 + g(9304)
g(9304) = 1 + g(9304 - 2^13) = 1 + g(1112)
g(1112) = 1 + g(1112 - 2^10) = 1 + g(88)
g(88) = 1 + g(88 - 2^6) = 1 + g(24)
g(24) = 1 + g(24 - 2^4) = 1 + g(8)
g(8) = 1 + g(8 - 2^3) = 1 + g(0) = 1
So iterating out we get:
9(24) = 1 + 1 = 2
9(88) = 1 + 2 = 3
9(1112) = 1 + 3 = 4
g(9304) = 1 + 4 = 5
So therefore:
f(9304) = 1 + 13 + 5 = 19 |
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| Posted by xandrani | 01/23/10 |
| The smiley faces with glasses should be '8 )'. |
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| Posted by xandrani | 01/23/10 |
| I have noticed a few comments stating that the answer is not a function... however aside from the function above I posted (which is one solution), I now also post another function which fits the other solution. Almost anything can be made in to a function.
g(x) = 1 + g(x - 2^⎣logx/log2⎦)
Where x ≠0 and g(0) = 0
f(x) = 1 + ⎣logx/log2⎦ + g(x)
Let's try and solve for x = 9304:
f(9304) = 1 + 13 + g(9304)
g(9304) = 1 + g(9304 - 2^13) = 1 + g(1112)
g(1112) = 1 + g(1112 - 2^10) = 1 + g(8 )
g(8 ) = 1 + g(88 - 2^6) = 1 + g(24)
g(24) = 1 + g(24 - 2^4) = 1 + g(8 )
g(8 ) = 1 + g(8 - 2^3) = 1 + g(0) = 1
So iterating out we get:
9(24) = 1 + 1 = 2
9(8 ) = 1 + 2 = 3
9(1112) = 1 + 3 = 4
g(9304) = 1 + 4 = 5
So therefore:
f(9304) = 1 + 13 + 5 = 19 |
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| Posted by xandrani | 01/23/10 |
| Damn smilies! I post yet again:
I have noticed a few comments stating that the answer is not a function... however aside from the function above I posted (which is one solution), I now also post another function which fits the other solution. Almost anything can be made in to a function.
g(x) = 1 + g(x - 2^⎣logx/log2⎦)
Where x ≠0 and g(0) = 0
f(x) = 1 + ⎣logx/log2⎦ + g(x)
Let's try and solve for x = 9304:
f(9304) = 1 + 13 + g(9304)
g(9304) = 1 + g(9304 - 2^13) = 1 + g(1112)
g(1112) = 1 + g(1112 - 2^10) = 1 + g(88 )
g(88 ) = 1 + g(88 - 2^6) = 1 + g(24)
g(24) = 1 + g(24 - 2^4) = 1 + g(8 )
g(8 ) = 1 + g(8 - 2^3) = 1 + g(0) = 1
So iterating out we get:
9(24) = 1 + 1 = 2
9(88 ) = 1 + 2 = 3
9(1112) = 1 + 3 = 4
g(9304) = 1 + 4 = 5
So therefore:
f(9304) = 1 + 13 + 5 = 19 |
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| Posted by xandrani | 01/23/10 |
| There are indeed many solutions to this one, here's another just for fun:
n = floor(x / 230)
f(x) = 14 - 7(x mod 2) + (1 - (x mod 2))((n^2 - n) mod 4)
f(9304) = 14 |
