
Lite 
Mystery Number 6
Category:  Logic 
Submitted By:  cnmne 
Fun:  (1.79) 
Difficulty:  (3.13) 
There is a tendigit mystery number (no leading 0), represented by ABCDEFGHIJ, where each numeral, 0 through 9, is used once. Given the following clues, what is the number?
1) Digit A is either a square number or a triangle number, but not both.
2) Digit B is either an even number or a cube number, but not both.
3) Digit C is either a cube number or a triangle number, but not both.
4) Digit D is either an odd number or a square number, but not both.
5) Digit E is either an odd number or a cube number, but not both.
6) Digit F is either an odd number or a triangle number, but not both.
7) Digit G is either an odd number or a prime number, but not both.
8) Digit H is either an even number or a square number, but not both.
9) Digit I is either a square number or a cube number, but not both.
10) Digit J is either a prime number or a triangle number, but not both.
11) A < B, C < D, E < F, G < H, I < J
12) A + B + C + D + E < F + G + H + I + J
Answer:
3605891247
A = 3, B = 6, C = 0, D = 5, E = 8, F = 9, G = 1, H = 2, I = 4, J = 7
1) 3 is a triangle number, but not a square number.
2) 6 is an even number, but not a cube number.
3) 0 is a cube number, but not a triangle number.
4) 5 is an odd number, but not a square number.
5) 8 is a cube number, but not an odd number.
6) 9 is an odd number, but not a triangle number.
7) 1 is an odd number, but not a prime number.
8) 2 is an even number, but not a square number.
9) 4 is a square number, but not a cube number.
10) 7 is a prime number, but not a triangle number.
11) 3 < 6, 0 < 5, 8 < 9, 1 < 2, 4 < 7
12) 3 + 6 + 0 + 5 + 8 = 22, 9 + 1 + 2 + 4 + 7 = 23, 22 < 23
A) First, determine what two subsets of numbers qualify for each digit. However, each digit can only be in one of the subsets, not both.
B) Digit A can not be 0 (a leading zero is not allowed).
C) Next, eliminate those numbers that do not satisfy Condition 11. Digit I can only be 4. Digit A can only be 3. Digit B can only be 6. Digit C can only be 0.
D) Digit D and Digit J must be some combination of 5 and 7. Digit E can only be 8. Digit F can only be 9. Digit G can only be 1. Digit H can only be 2.
E) To satisfy Condition 12, Digit D is 5 and Digit J is 7.
Comments on this teaser
Most Popular  Hardest  Easiest
Privacy  Terms
Copyright © 2003