### Brain Teasers

# The Four Jays

Four friends named Jane, June, Jean and Jenny discovered that, if a different non-zero integer was assigned to each letter of their names and added together, it produced their ages.

June is 17, Jenny is two years older, while Jane and Jean are both sweet 16. All the girls agree that June is in her prime. Can you find the numbers the girls assigned to each letter of their names?

(There are two possible answers.)

June is 17, Jenny is two years older, while Jane and Jean are both sweet 16. All the girls agree that June is in her prime. Can you find the numbers the girls assigned to each letter of their names?

(There are two possible answers.)

### Hint

prime...### Answer

J=2; U=7; N=5; E=3; A=6; Y=4or

J=3; U=7; N=5; E=2; A=6; Y=4

The little clue 'June is in her prime' should have helped, as it suggests that all the numbers in her name are prime numbers. As the total is 17 all the numbers must be less than 10, so:

J=2; U=7; N=5; E=3 (or J=3; U=7; N=5; E=2)

Setting these numbers in the word Jane or Jean we can conclude that

16=2+A+5+3, so A=6.

Putting these numbers in the word Jenny in the same way we find Y=4.

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