### Brain Teasers

# Camel and Watermelons

In city A on desert, there is a guy with his camel and 1000 watermelons. He wants to sell the watermelons in city B where a fair takes place. The distance between A and B is 99km.

However, the camel can only carry a maximum of 100 watermelons at a time. In addition to that, the camel eats one watermelon per each kilometer it travels.

The guy wants to bring to the fair as many watermelons as possible. How can he do it? And what is the maximum number?

However, the camel can only carry a maximum of 100 watermelons at a time. In addition to that, the camel eats one watermelon per each kilometer it travels.

The guy wants to bring to the fair as many watermelons as possible. How can he do it? And what is the maximum number?

### Hint

What if the distance was just 1km? What if it was 2? What if it was 5?### Answer

If the distance was 1, the obvious maximum would be 981 (as the camel needs to travel 19 times). If the distance was 2, the result is same as if the man had 981 watermelons and to go only 1km, so the result would be 962. When using this method, we can calculate that the final number of watermelons is 140. (Note: The result for distance of 6 is 886 but from this moment the camel needs to travel only 17 times to get all the watermelons 1km further, so the result for distance of 7 is 869)Hide Hint Show Hint Hide Answer Show Answer

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