Brain Teasers
Four 0's
Using only four ZERO'S (0) and any Mathematical Operations/Symbols, obtain the number 24.
Answer
0! = 1(0! + 0! + 0! + 0!)! = 24
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I thought about that! I thought 0! would be 0 because all the numbers starting from one and going up to that number. I didn't realize that 0 had an acception. After Googleing it, I found out that you just figure out all of the combinations of all of the numbers below it. EXAMPLE: 3! is 6. 1,2,3; 2,1,3; 3,2,1; 2,3,1; 3,1,2; 1,3,2. Zero is the only exception to the multiplication rule as it has one combination, just 0.
All in all, great teaser! Full stars and in my favorites.
All in all, great teaser! Full stars and in my favorites.
Hey hey Thank you
Ok, I'll say it first.....huh?
Does 000=24 work?
sorry 00 : 00=24
Also 0/0 is considered to be indeterminate so it also has the ability to equal 24. If A*B=C, then C/B=A. Since 24*0 = 0, then the reverse must also be true, 0/0=24.
And we learned that 0/0 is the same with infinit/infinit and it makes no real sense.
((0!+0!)^(0!+0!))! = 24
I thought of putting two pairs of 0s one above the other to make two 8s. Then take square root of 8+8. Then factorial of 4.
Guess I've spent too long in the Trick category!
Top Teaser!
Guess I've spent too long in the Trick category!
Top Teaser!
lol... that was funny
cheers
cheers
In addition to 0! = 1, there is cos(0) = 1.
It sounds impossible, but if you guys say its so, so be it. I have nothing (0) to contribute to (0), so I cannot expect anything frin 0!, but (0). But always remember, No matter how many times you say 0!+0!+0!+0! it will always mean Zero...
too much math for me
0!=1.
4!=24, As there are 24 combinations of 1, 2, 3, and 4.
For 0, there's one combination: 0.
And yes, I know 4!=1*2*3*4.
4!=24, As there are 24 combinations of 1, 2, 3, and 4.
For 0, there's one combination: 0.
And yes, I know 4!=1*2*3*4.
Nov 08, 2010
" Also 0/0 is considered to be indeterminate so it also has the ability to equal 24. If A*B=C, then C/B=A. Since 24*0 = 0, then the reverse must also be true, 0/0=24."
** False -- 0/0 is indeterminate, so it cannot be determined. It cannot be used.
"((0!+0!)^(0!+0!))! = 24"
Good one above!
"I thought of putting two pairs of 0s one above the other to make two 8s. Then take square root of 8+8. Then factorial of 4."
The above is creative, but it doesn't count.
" In addition to 0! = 1, there is cos(0) = 1. "
The above is okay if trig expressions are allowed.
Along with the factorial, a solver can use gamma(n) = (n - 1)! for
n >= 1. And the inverse function of
gamma(n), say invgamma(x)
could be used. For example,
invgamma(6) = 4, because
gamma(4) = (4 - 1)! = 3! = 6.
** False -- 0/0 is indeterminate, so it cannot be determined. It cannot be used.
"((0!+0!)^(0!+0!))! = 24"
Good one above!
"I thought of putting two pairs of 0s one above the other to make two 8s. Then take square root of 8+8. Then factorial of 4."
The above is creative, but it doesn't count.
" In addition to 0! = 1, there is cos(0) = 1. "
The above is okay if trig expressions are allowed.
Along with the factorial, a solver can use gamma(n) = (n - 1)! for
n >= 1. And the inverse function of
gamma(n), say invgamma(x)
could be used. For example,
invgamma(6) = 4, because
gamma(4) = (4 - 1)! = 3! = 6.
Jan 15, 2011
I didn't understand it..what do you mean by 0!?
0! = 0 factorial.
The factorial of n is the product of all positive integers less than or equal to n.
0! is a special case that is explicitly defined to be 1.
The factorial of n is the product of all positive integers less than or equal to n.
0! is a special case that is explicitly defined to be 1.
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