Brain Teasers
Kebab Combination
Mad Ade is in a bit of a dilemma. He has accidentally locked his Kebab in a combination safe. Only this safe uses letters instead of numbers. Only he has forgotten the combination.
These are the 6 letters used in the combination: A, B, C, D, E, F; with none of them being used twice.
Here are three incorrect guesses Mad Ade has already made at the combination.
C B A D F E
A E D C B F
E D F A C B
In the FIRST guess, only ONE letter is in its correct place.
In the SECOND guess, only TWO letters are in their correct places.
In the THIRD guess, only THREE letters are in their correct places.
Each of the 6 letters is in its correct place once.
What is the correct combination needed to rescue the Kebab?
These are the 6 letters used in the combination: A, B, C, D, E, F; with none of them being used twice.
Here are three incorrect guesses Mad Ade has already made at the combination.
C B A D F E
A E D C B F
E D F A C B
In the FIRST guess, only ONE letter is in its correct place.
In the SECOND guess, only TWO letters are in their correct places.
In the THIRD guess, only THREE letters are in their correct places.
Each of the 6 letters is in its correct place once.
What is the correct combination needed to rescue the Kebab?
Answer
The combination was EBDACF or AEFDCB (either will work).Hide Answer Show Answer
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Comments
i got it but it took a while :-)
The way I got this was to guess which letter
in the top row was correct. Say we guess "B".
Then D can't be in the correct position in the
third row (because it shares a column with B), so it must be correct in the second row.
Looking down from D in the second row, we find that
F can't be in the correct position in the third row either,
so it must be correct in the second row. Fortunately, the
letter below the second row F is B, closing the loop with the original
letter. That means that the the remaining letters can
all be correct in the third row, leading to the solution
EBDACF. Checking the other letters in the first row, we find
that D also leads to a 3-letter loop: D->A->E->D, so that
provides the second solution, AEFDCB. The other four letters
all lead to loops that are longer than three letters, which
means that they could not have three letters correct in the third row.
in the top row was correct. Say we guess "B".
Then D can't be in the correct position in the
third row (because it shares a column with B), so it must be correct in the second row.
Looking down from D in the second row, we find that
F can't be in the correct position in the third row either,
so it must be correct in the second row. Fortunately, the
letter below the second row F is B, closing the loop with the original
letter. That means that the the remaining letters can
all be correct in the third row, leading to the solution
EBDACF. Checking the other letters in the first row, we find
that D also leads to a 3-letter loop: D->A->E->D, so that
provides the second solution, AEFDCB. The other four letters
all lead to loops that are longer than three letters, which
means that they could not have three letters correct in the third row.
I got ADFCBE which also seems to work
Nope, that would have three guesses correct in the second row.
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