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Time of Arrival
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Adam, Ben, Carl, and David all left this morning for vacation. All left in separate cars, headed for the same destination. Adam leaves first, followed by Ben, then Carl, and finally David. Adam leaves home at 4:31 and arrives at 8:12; Ben leaves at 5:22 and arrives at 9:20; and Carl leaves at 6:13 and arrives at 10:18. If David leaves home at 7:41 and his time of arrival follows the same pattern as each of his friends, what time did he arrive at the vacation spot?
Hint
Adam departed at 4:31 .4+ 3+ 1 = 8 ; 4x3x1 = 12
Answer
12:28He left home at 7:41 .
7+4+1 = 12 ; 7x4x1 = 28
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Comments
I think the hint needs to be in the main part of the problem. Without looking at the hint, 2nd trip was 17 mins longer than the first, 3rd trip was 7 mins longer than the 2nd so 4th trip will be 3 min less than the 3rd following that pattern. There are lots of patterns!
i really enjoyed solving this one. ist really challenging teaser in a long time. congrats.
The hint is not really a hint at all. It's pretty much the answer to the teaser. Other than that, it was an excellent teaser. A great challenge!
I agree with jimbo in the sense that there are many patters that can be found.. I did exactly the same thing he did. And yes, the hint is the answer.
This is a good challenge.
I didn't like this one and didn't work it. How long individual people spend on the road to a destination varies with how many stops they make, to buy gas, to use the restroom, to admire a view or take pictures. It didn't look logical to me unless they were robots.
People say this is hard. I thought so until I looked at the hint. Ruined the whole point
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