### Brain Teasers

# Tricky Maths Symbols

Each symbol represents one and only one of the numbers from 1-9 inclusive.

All the terms are added except the last one, which is a multiplication # * $ = &$.

&$ is a double digit number.

Solve :

\ + > = &$

^ + % = &$

? + > + @ =&$

\ + ^ + & = &$

# + ? + ^ = &$

# MULTIPLIED by $ = &$

All the terms are added except the last one, which is a multiplication # * $ = &$.

&$ is a double digit number.

Solve :

\ + > = &$

^ + % = &$

? + > + @ =&$

\ + ^ + & = &$

# + ? + ^ = &$

# MULTIPLIED by $ = &$

### Hint

Need to use a lot of logical thinking and deduction: For a start: if \ + > are the biggest numbers possible, 9 and 8, the &$ = 17& is non zero so it must be 1

& = 1

### Answer

To check your answer:1 = &

2 = @

3 = #

4 = ?

5 = $

6 = \

7 = %

8= ^

9 = >

6 + 9 = 15

8 + 7 = 15

4 + 9 + 2 = 15

6 + 8 + 1 = 15

3 + 4 + 8 = 15

3*5 = 15

For a complete solution:

\ + > = &$

^ + % = &$

Starting with the sums with only two terms; because two terms added together can only have a maximum of (9+8)= 17 and the first digit of &$ is non-zero, so the minimum is 12

Therefore & is 1

# MULTIPLIED by $ = &$

something multiplied by something else must be between 17 and 11 (from above)

There are only a few combinations, but only one possibility here

2 * 6 = 12

2 * 7 = 14

2 * 8 = 16

3 * 4 = 12

3 * 5 = 15

The second multiplying term is equal to the second digit of the answer = 5

Therefore # is 3 and $ is 5

Filling in what's known:

\ + > = 15

^ + % = 15

? + > + @ = 15

\ + ^ + 1 = 15

3 + ? + ^ = 15

\ + > = 15

^ + % = 15

These symbols must be 6, 7, 8, 9 because otherwise a result of 15 can't be got.

They must be either 9 + 6 or 7 + 8 in some order.

\ + ^ + 1 = 15

\ + ^ = 14 they can't be 9 (because 5 is already known.)

So they must be 8 and 6 in some order.

That also means > and % must be 7 and 9 in some order.

? and @ must be 2 and 4 in some order (They are the only symbols left for the only two numbers), and ? + @ = 6

? + > + @ = 15

That means > must be 9

\ + > = 15

That means \ = 6

\ + ^ = 14

^ is equal to 8

and % = 7

Filling in what's known again:

6+ 9 = 15

8 + 7 = 15

? + 9 + @ = 15

6 + 8 + 1 = 15

3 + ? + 8 = 15

? must be 4

and therfore @ = 2

1 = &

2 = @

3 = #

4 = ?

5 = $

6 = \

7 = %

8= ^

9 = >

6 + 9 = 15

8 + 7 = 15

4 + 9 + 2 = 15

6 + 8 + 1 = 15

3 + 4 + 8 = 15

3*5 = 15

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