Pass the Candy!
|Fun:|| (2.66) |
|Difficulty:|| (2.2) |
A group of 9 friends have a package of 40 W&W's chocolate candies to share. They each, one at a time, take a prime number of W&W's to eat. After that, the bag is empty. Exactly four of the friends took a number of W&W's that had previously been taken by someone else. Of the group, the number of people who took exactly 5 is twice the number of people who wear glasses.
Without any regard to the order in which they were taken, what individual quantities of W&W's were taken?
Comments on this teaser
|Posted by Jellonz||10/03/13|
|There is a second set of primes that can include 13 and satisfies the even number of 5s rule.
2, 3, 3, 3, 3, 3, 5, 5, 13
This set can also meet the 'Exactly four of the friends took a number of W&W's that had previously been taken by someone else' rule if this sentence is interpreted differently, as: 4 of the friends took the same number of W&Ws as 1 of the other friends, i.e 5 friends took the same number, (5 friends taking 3 each).|
|Posted by eighsse||10/03/13|
|When I mention the only set that can include 13, I am referring to the only set that follows all the rules besides the final, slightly more cryptic clue. And I can see what you mean about the reinterpretation. But I still think it is quite clear. Maybe one way it could be made clearer would be something like: "Exactly four of the friends took a duplicate number that any of the others had taken previously."|
|Posted by lewis123||10/12/13|
|Doesn't 1,1,2,3,5,5,5,5,13 work as well?|
|Posted by eighsse||10/12/13|
|1 is not prime.
Common mistake though, so don't feel bad.|
|Posted by charlottes-odd||12/03/13|
|My brain is not in a clever mood tonight, long day of working on shows does that to you I'm afraid :(|
Most Popular | Hardest | Easiest
Privacy | Terms
Copyright © 2003