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Math Madness
Draw a 3 x 3 grid so it has 9 boxes. You have to write the numbers 0 to 8 in each box so that going side to side, up and down, and diagonally the sum is 12. Each number can be used only once.
Answer
5 0 76 4 2
1 8 3
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jcjcisdabomb,
That was da BOMB.
That was da BOMB.
Threre is a rule for doing this. Start with 0 in an outside middle square and move diagonally either way. If you go outside the boxes slide to the end of the row or column. If the digonal square is occupied or you go outside on a major diagonal then drop to the square below. These rules work for any n x n odd magic square. Good puzzle!
The hint on this should be this:
GO FOR THE DIAGONALS FIRST! This will make the rest of the work easier.
Have fun! It took me multiple tries and finally reducing the possible middle-box numbers to 3 possibilities.
-Steve
GO FOR THE DIAGONALS FIRST! This will make the rest of the work easier.
Have fun! It took me multiple tries and finally reducing the possible middle-box numbers to 3 possibilities.
-Steve
ehh good one
this is similiar to the one u had to fit 1-9 into nine grids so that each line sums up to 15. the solution is also similiar. for the 15, u get all the even numbers at the corners and 5 in the center. this one, u get all the odd numbers at the corner and 4 in the center.
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