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## The Truel

Probability puzzles require you to weigh all the possibilities and pick the most likely outcome.

 Puzzle ID: #22672 Fun: (2.83) Difficulty: (2.38) Category: Probability Submitted By: brianz Corrected By: eighsse

Mr. Black, Mr. Gray, and Mr. White are fighting in a truel. They each get a gun and take turns shooting at each other until only one person is left. Mr. Black, who hits his shot 1/3 of the time, gets to shoot first. Mr. Gray, who hits his shot 2/3 of the time, gets to shoot next, assuming he is still alive. Mr. White, who hits his shot all the time, shoots next, assuming he is also alive. The cycle repeats. All three competitors know one another's shooting odds. If you are Mr. Black, where should you shoot first for the highest chance of survival?

### Hint

Think from the points of view of Mr. Gray and Mr. White, not just Mr. Black.
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## Comments

 Melly13 May 05, 2005 Ok that brain teaser is very confusing! TO many names... but it's not a bad one phrebh May 05, 2005 The teasers are getting violent. catzgirl_95 May 05, 2005 EZ but fun markmonnin May 05, 2005 I didn't get it right... but I enjoyed the answer! Ozymandias May 05, 2005 Good one!! norcekri May 05, 2005 Considering that this is an old classic from the literature, I'm surprised to see this here. Don't the editors know about copyright violation? vikingboy May 06, 2005 not only is it an old story, but I also think it's highly questionable. The point is, Mr Black is hoping that Mr White is taken out of the picture. By shooting the ground, he hopes that Mr Gray will shoot at Mr White, with a 67% chance of hitting him. If Gray does kill White, then black has a 33% chance of killing Gray, followed by Gray having a 67% chance of killing Black, this goes on until one dies. If Black shoots the ground, and Grey does not kill White, White then kills Grey, and Black has a 33% chance of killing White, if Black misses, White kills him 100% of the time. If I'm Mr Black, I take my shot at Mr White. 33% of the time I kill him, and now it's me against Mr Gray and I have a chance. 67% of the time it reverts back to the previous scenario of Grey vs White, and nothing changes. Give me that added chance. brianz May 06, 2005 Here's the complete solution, vikingboy. If Mr. Black shoots the ground, there is a 1/3 chance that he will be left with Mr. White and a 2/3 chance he will be left with Mr. Gray. If he is left with Mr. White, he has a 1/9 chance of survival. If he is left with Mr. Gray, his probability of survival is 1/3((2/9)^0+(2/9)^1+(2/9)^2+(2/9)^3...) which is an infinite series that approaches to 3/7 (I think). Therefore, If Mr. Black shoots the ground, his total chance of survival is 1/9+3/7*2/3=1/9+2/7=25/63 Now, if Mr. Black shoots Mr. Gray, there is a 1/3 chance that he will be left with Mr. White and die and a 2/3 chance that he will miss and that we will go into the same situation as if Mr. Black just shot the ground. Therefore, his chance of survival is 25/63*2/3=50/189 If Mr. Black shoots Mr. White, there is a 2/3 chance that he will miss and he will have a 25/63 chance of survival. There is also a 1/3 chance that he will kill Mr. White and we will go into the situation with just Mr. Gray and Mr. Black, except this time Mr. Gray shoots first. Therefore, Mr. Black has a 1/3*2/7 chance of survival. So his total chance of survival is 2/21+50/189=68/189 When comparing the three fractions, the chances are 75/189, 50/189, and 68/189. Therefore, Mr. Black should shoot the ground. brianz May 06, 2005 Okay, I know that was kinda complicated, but think about it this way. If Mr. Black is left with Mr. Gray and Mr. Black gets to shoot first, there is an unkown probability of survival, let us say x. If Mr. Black shoots the ground, his chance of survival is 1/9+2/3 x. If Mr. Black shoots Mr. Gray, his chance of survival is 2/3*(1/9+2/3 x), so he should not shoot at Mr. Gray. If Mr. Black shoots Mr. White, his chance of survival is 2/3*(1/9+2/3 x)+1/3*1/3*x. Now we must prove that 1/3*(1/9+2/3 x) is more than 1/3*1/3*x. First we can simplify to try to prove 1/9+2/3 x > 1/3*1/3*x. We can deduce that x is slightly larger than 1/3, and we know that 1/9+2/3*1/3 > 1/3*1/3*1/3, so we know this will always be true for any value of x greater than 1/3. bobthesnail May 06, 2005 Slightly easier (I think) way to look at it. You are Mr. Black. Do you want to aim at Mr. Gray? Let's say you hit him. Then you instantly die from Mr. White. Survival rate from hitting Mr. Gray = 0 Do you want, then, to aim at Mr. White? Let's say you hit him. Then it's Mr. Gray vs Mr. Black with Mr. Gray getting the first shot. Since there's a 2/3 probability in this case of Gray killing Black with the first shot, Black's chance of surviving such a duel is less than 1/3. Let's say you miss. Then, Mr. Gray's turn to aim. If he aims at Mr. Black, and hits him, he instantly dies. Thus, aiming at Mr. Black is stupid. Let's say Mr. Gray aims at Mr. White. If he hits Mr. White, he then is in a 2 person duel with Mr. Black. Let's say he misses. Then Mr. White has his choice of killing Black or Gray. Either way, his opponent gets one chance to take him out. Thus, Mr. White would kill Gray. Gray, knowing that, will not shoot at the ground, knowing that White would instantly kill him. Thus, Gray will shoot at White. When it gets back around to Mr. Blacks turn, only one opponent will be left. Either way, Mr. Black gets AT LEAST a 1/3 chance of shooting that person, as opposed to the LESS THAN 1/3 chance that he would have if he were in a 2 person duel with Gray and Gray shooting first. (Mr. Black has exactly 1/3 chance of winning a duel between him and White if Grey had killed White. He has a slightly better chance if he's facing Gray, since Gray's aim isn't 100% and Black gets a second turn.) Interesting side note: logic stays the same if Gray's aim goes up to 100% and Blacks goes infinitely close to 0. xsadclowneyezx May 06, 2005 foxxie celebrity May 06, 2005 I guess I liked it it was okay... vikingboy May 06, 2005 alright, don't get your thongs all twisted...I understand the odds just fine, what I overlooked was that if Black does kill White, Gray gets the first shot at Black. If he shoots the ground AND the others do as expected Black gets to shoot first. Keep in mind that you are assuming that the other two have the same information you do, and that they act logically. Still say that this one has been around forever. Master_Yoda May 06, 2005 What if Mr. Gray or White decide to shoot and Mr. Black. Then Mr. White would have the better chance of surviving because Mr. Black would shoot at the ground and Mr. Gray would shoot him. leaving Mr. White to shoot Mr. Gray. Too many "if's" brianz May 07, 2005 But since Mr. White is better than Mr. Black, Mr. Gray would rather shoot at him for his highest chance of survival, Master Yoda. cracker May 07, 2005 It was confusing! What is a truel anyway? vikingboy, lay off being too smart. You are making me look pretty stupid, I can't figure out these confusing riddles. It isn't my fault that I am not as smart as ya'll! changegurl May 07, 2005 I just use plain on common sense on this. I so! proud of MYSELF!!!!!!!!!!!!!!!!!!!!!!! brianz May 07, 2005 Cracker, a truel is supposed to be like a duel except there are three people fighting in it. However, it is not actually a real word. libra0890 May 07, 2005 SOOOOOOOOOOOOO STUUUUUPPPPIIIIIIIIDDDDDDDDDDDD. SO DUMB Question_Mark May 07, 2005 I guessed the air. Ground, air, its all the same to me. darthforman May 08, 2005 my head hurts zonahobo May 09, 2005 Someone should shoot Mr. Black for getting in a fight with two guys who are such better shots than him .. classic or not, as long as it doesn't duplicate another post .. what's the harm .. I enjoyed it. jeSuS123 May 09, 2005 i didnt kno ground was a option Maimai May 12, 2005 I feel ultra stupid. I have a head ache... Way too many names... I think Mr. Black should just shoot everybody three times and not follow the rules. Y'know... just a suggestion... Javian May 18, 2005 Good one...made you think sniperkid990 May 24, 2005 my brain is pulsing toooooo much informatin to proses Poker Jun 10, 2005 You think three people has a strange outcome? I tried to figure it out for four (Mr. Red with 1/4, Mr. Yellow with 2/4, Mr. Green with 3/4, and Mr. Blue with 4/4), and there's a very strange result. Mr. Yellow has the best odds, followed by Mr. Green, Mr. Red, and Mr. Blue, in that order, if everyone follows ideal strategy. Mr. Red fires at Mr. Blue. If he misses, Mr. Yellow fires - but not at Mr. Blue or even at Mr. Green, but at Mr. Red! If he misses, Mr. Green fires at Mr. Blue. If he misses, Mr. Blue bumps off Mr. Green. In any case, once it's down to three people, it's the same strategy as the truel shown here (even if Mr. Blue was bumped off, although it was significantly harder to figure out). brianz Jun 11, 2005 That seems like a pretty interesting problem, Poker. I'll try to figure it out some day. Note, however, that in this problem, we aren't trying to figure out who has the highest probability of staying alive, but rather where Mr. Black should shoot to have the highest probability of staying alive. In my problem, Mr. Black has a 75/189 chance of staying alive, Mr. Gray has a 8/21 chance of staying alive, and Mr. White has a 2/9 chance of staying alive. Therefore, Mr. Black has the highest chance of survival. Additionally, in your problem with 4 people, I think it would be better for Mr. Red to shoot at the ground too, as this would guarantee a 1 on 1 match with Mr. Red against someone else, with Mr. Red having the first shot. Poker Jun 15, 2005 Not quite, since then it would be down to three people, not two. Red actually has better odds if he kills Blue than if he doesn't kill anyone. I've got to warn you, though, it's tricky to figure out (especially for Red, Yellow, and Green left, since they all sometimes miss - at least, that's what I thought when I first came to that point). And some of those fractions can get pretty large. For example, at the start, Blue wins 21/256 of the time, Yellow wins 11727/28840 of the time, Green wins 40257/149968 of the time, and Red wins 2914283/11997440 of the time! If this is what it's like with four, with five the fractions must be huge! Wendy510 Jun 23, 2005 it's good and complicated, but how come so many of you people are trying to explain it when it's already a good explanation in the answer? dolphingurl12 Jul 15, 2005 What I wanna know, it how do they know how often they hit or miss cause this sounds like something you can only do once. jhonertwert Aug 14, 2005 i wanna shoot the person who rote that shoulder_angel Sep 22, 2005 Wow! How do you think of things like that? It all makes my head spin! realm2346 Oct 31, 2005 At first, I said that Mr. Black should shoot Mr.White because he never misses his target......then I said hit the ground. legodude Dec 02, 2005 I personally think that this teaser is awesome. It makes you think (sadly, I did not solve it correctly because I overlooked the possibility of shooting the ground). -An Interesting Note- I've discovered (with the necessary aid of a graphing calculator) that the limit of x^0+x^1+x^2+x^3+x^4+x^5+x^6... where 0â‰¤xâ‰¤1 is (-1)/(x-1) . -Comments on the Above- The boundaries for x (0 and 1) are inclusive in this case, but inserting the boundaries into the equation wields 1 and 1/0=âˆž*, respectively. The solution for x=0 exists because 0^0+0^1+0^2... =0^0=0/0, which can equal any real number (I also discovered this, but I found out that it had already been found out) (say a=0 and b is real, therefore ab=0, b=(0/a)=(0/0), thus 0/0 can equal any real number), equals, in this case, 1. As for the second boundary, you would expect 1^0+1^1+1^2...=1+1+1... to equal âˆž. If you would rather not go into the abstract realm of division by zero, just change both inequality signs to legodude Dec 02, 2005 (cont. from above) legodude Dec 02, 2005 less than signs. * I say this tentatively, because I think that it is generally accepted. I have not experimented enough with the concept of infinity to feel certain that it is equal to 1/0. It's an interesting topic, though. paul726 Dec 11, 2005 I have to agree that Black should aim at White with his first shot. Unless he aims at and kills Gray with his first shot, he will get to shoot again. (unless either of the others is stupid enough to shoot at Black while their other opponent is still breathing) In any case, brainz, I disagree with your post of May 5 where you state that Black has a 1/9 chance of survival vs. White. His chance is 1/3. If he hits his only shot, he wins, if he misses, he's dead. This is assuming, of course, that he's facing White because White wisely took out Gray with his first opportunity. SPUTNIK2 Jan 20, 2006 that was a real blast I gave it my best shot! thanks, good teaser Jimbo Feb 25, 2006 An oldie but a goody. Teasers with completely unexpected answers are always more interesting. And besides, we'll all have to go and investigate the quadruel won't we? Watch this space! shadow-x Mar 03, 2006 ok i think that he should shoot at the guy who always hits cuz he would probly miss, and then the other guy would shoot at the guy who always hits then he wuold be dead;.... buenos May 09, 2006 This teaser isn't racist...... right...? elduce Nov 03, 2006 Isn't is a 'dual' and not a 'truel'? I looked up 'truel' and it doesn't exist. elduce Nov 03, 2006 Isn't it a 'dual' and not a 'truel'? I looked up 'truel' and it doesn't exist. extremetigerfan Jul 26, 2007 Isn't shooting at Mr. White and missing the same as shooting the ground? Why not take the 1/3 chance that you might actually kill the most potent person first? does your probability of dying go up if you kill White on the first shot? I don't want to work it all out, just tell me. zembobo May 21, 2008 No, shooting Mr White and hitting him gives Mr Grey only one target...YOU. You want Mr white alive because you can safely assume Mr grey will shoot at him and probably hit him. If Mr Grey misses, Mr White will shoot him first giving himself a 1/3 chance to live. My biggest problem with this teaser is that shooting the ground was NOT an option. It clearly said that they were taking turns shooting each other, not the ground. Still, got me thinking. zembobo May 21, 2008 I meant to say in my previous comment..."giving himself a 2/3 change to live", not "1/3" sorry about that..guess I should proof read a little better. bbbz Jul 20, 2008 it actually doesn't matter who or what black shoots at because if you've seen the movie, "the white, the gray and the black" you would know that mr white takes the bullets out of mr blacks gun the night before. donga Aug 19, 2008 good one!!! i enjoyed the question and the explanation is correct but something is boggling me, why should Mr.white target Mr.Grey ? definitely Grey has more chance of killing him than black , but we are dealing with probability so white will choose Grey 2/3 times and black 1/3 times . but in the case of Grey , choosing black will mean instant death , so he always targets white. opqpop Jan 26, 2010 donga, suppose you are white. If you shoot at black and kill him, it becomes you vs. gray. If you shoot at gray and kill him, it becomes you vs black. Since gray is a better shooter, it is clear you would prefer the latter case: you vs black. Hence, white always shoots for gray. Ricorum Nov 23, 2010 If Mr. Black only hits what he's aiming at 1/3 of the time, does that mean he has a 66% chance of missing the ground? No_Eyed_Fsh Nov 23, 2010 Even the worst shooter should hit the ground... I think. builder Nov 23, 2010 Shooting the ground is a guaranteed hit. Wouldn't that mean the next two shots would miss their target. Might as well try to take out white. Actually each shot has the same chance of hit or miss. There is no guarantee that in 3 shots one will be a hit. angitude21 Nov 23, 2010 Someone has way too much time on their hands!!! This was beyond stupid and who cares!!! TallTimber Nov 23, 2010 I lost interest way before getting to the end of the question. patiencewithaP Nov 23, 2010 Good teaser! But it made my head hurt! I say Messrs. Black, White, and Gray should put down their guns and go have a drink together instead. yash23 Nov 23, 2010 I find this racist XD dodgerh8ter Nov 23, 2010 Hey, why am I Mr. Pink? Because you're a f*****. Why can't we pick our own colors? No way, no way. Tried it once, doesn't work. You got four guys all fighting over who's gonna be Mr. Black, but they don't know each other, so nobody wants to back down. No way. I pick. You're Mr. Pink. Be thankful you're not Mr. Yellow. jcann Nov 23, 2010 This is one of the worst teasers I've ever seen on this site, as are also some of the comments. (Especially the one above.) I used to enjoy coming to this site every day, but it doesn't seem the same anymore. crazyfunkychik Nov 23, 2010 I think he should have shot Mr.White first because Mr.White never misses so that would be a relief to get rid of him but i do see your point now 2big2fail Nov 24, 2010 if i were mr. black i'd shoot myself in the foot and call it a day. after all, the question is about survival, not about winning. j_winburn Nov 24, 2010 Hey, if Mr. Black only hits his target 1/3 of the time, does that mean if he shoots at the ground he will probably miss? Where will the errant shot go? Could he accidentally hit one of the other two? Or himself?!!? Gadgetphile Nov 23, 2013 I've read another version of this that claims you have a greater chance of survival if you shoot in the air. Is that true and if so why? auntiesis Nov 23, 2013 My brain hurts. bestgirl Nov 23, 2013 Who cares? gaylewolf Nov 23, 2013 MY brain hurts, too and WHO cares? OK It's an interesting puzzle, but it's either too hard, or too early! Just nice to say hi to all of you! jaycr Nov 23, 2013 Too early for this one, but I'd be lying if I said I'll come back later. Hi back to you Gayle! jeRussell Nov 23, 2013 Unfortuneately for Mr. Black he can only hit his target 1/3 of the time. Therefore he will probably miss the ground and hit either Mr. Gray or Mr. White. After the shooting is over, Mr. Pink runs away with all the money. Babe Nov 23, 2013 I am with phrebh! Now violence has infested our brain games. Isn't there enough in the world already?? eighsse Nov 23, 2013 I worked out the approximate percentages, but I was assuming that the solver is expected to assume that the other people's targets were randomly chosen when they had a choice between two. In other words, when it's Mr. Gray's turn and all three are still alive, I figured we were supposed to give a 50% chance that he shoots at me and a 50% chance that he shoots at Mr. White. It didn't really say in the teaser. Also, I didn't think about the shooting-at-the-ground option. So I got this: Shoot at Mr. White first: 25.8% win Shoot at Mr. Gray first: 12.3% win And if you use the same method for shooting at the ground: 34.1% win So yeah, shooting at the ground is best either way. eighsse Nov 23, 2013 And in defense of my reasoning, it never even says in the teaser that the three people know each other's shooting percentages. hienvu Jul 03, 2014 The answer is not enough. 3 choices: shoot Gray, shoot White and no shoot (shoot ground) If shoot Gray, is Black better off is Gray is dead? No because White will kill him => not shoot Gray If shoot White, is Black better off if White is dead? If White die => Gray will start first at 1vs1 combat with Black => prob Black alive = 1/7 If White alive => 2 scenarios: Gray may kill White => Black will start first => Black is better off. If Gray does not kill White, White will kill Gray => Black will start first at 1vs1 combat with White => prob Black alive=1/3 => Black is better off as well. Therefore, Black will be better off if White is alive. Kim_Jong-il Aug 04, 2014 Side to consider: Suppose Mr. Black has shot at the ground. Now it is Mr. Grey's turn. Suppose Mr. Grey shoots at Mr. White. If Mr. Grey kills Mr. White, then Mr. Black and Mr. Grey obviously shoot at each other, giving Mr. Grey a 3/5 chance of survival. Interesting. Suppose it comes to Mr. White's turn, with all 3 men alive. Suppose Mr. White shoots at Mr. Grey. Mr. Grey dies and Mr. White now duels with Mr. Black giving Mr. White a 2/3 chance of survival. Now we can provide insight on the best strategies for Mr. Grey and Mr. White. In the most simplified form, let us assume any strategy must be consistent. That is to say that, given a set of circumstances, the same action is always taken. Then we have two Nash equilibria: Mr. Grey and Mr. White both choose to shoot each other when all 3 men are alive, or both men choose to also shoot the ground when all three men are alive (this game is assumed to give a result of all three men living indefinitely with no dying from other means, although does not take into account the obvious drop in quality of life). In this simplified version, these two men have NO OPTIMAL STRATEGY. This is because the best strategy for one of the men changes if the other man's chosen strategy changes. Let us now look at the more complex situation in which we assume the two men pick some probabilities g (for Mr. Grey) and w (for Mr. White), such that whenever it is their turn and all 3 men are alive, the chance of them deciding to shoot the other is g or w with the alternative being a ground shot. This scenario retains the two equilibria from the previous scenario. Importantly, for any g Kim_Jong-il Aug 04, 2014 for any g Kim_Jong-il Aug 04, 2014 My comments keep getting cut off for some reason.

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