Brain Teasers
The Dice Game
Xavier and Rex were playing a game that involved 5 dice. In each turn, they would roll the 5 dice. Each face of the die is worth a different amount of points. On their first 2 shots, they rolled this:
Xavier 1: 1, 3, 3, 4, 6 = 177 points
Rex 1: 2, 4, 4, 5, 6 = 268 points
Xavier 2: 1, 1, 1, 4, 4 = 203 points
Rex 2: 1, 2, 3, 4, 6 = 216 points
Using this information, can you work out how many points Xavier and Rex each got on their third turn and how many points each face is worth?
Xavier 3: 1, 2, 2, 3, 4 = ?
Rex 3: 1, 3, 4, 6, 6 = ?
Xavier 1: 1, 3, 3, 4, 6 = 177 points
Rex 1: 2, 4, 4, 5, 6 = 268 points
Xavier 2: 1, 1, 1, 4, 4 = 203 points
Rex 2: 1, 2, 3, 4, 6 = 216 points
Using this information, can you work out how many points Xavier and Rex each got on their third turn and how many points each face is worth?
Xavier 3: 1, 2, 2, 3, 4 = ?
Rex 3: 1, 3, 4, 6, 6 = ?
Hint
Xavier scored more than Rex and the difference between the two total scores is 26 points.Answer
Xavier: 281 (Total: 661)Rex: 151 (Total: 635)
1 = 25 points
2 = 77 points
3 = 38 points
4 = 64 points
5 = 51 points
6 = 12 points
From Xavier's first shot and Rex's second shot, we can deduce that a 2 is worth more than a 3. From Xavier's second shot, we can deduce that a 1 is worth an odd number. By trial and error we can work out the value of each face.
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Comments
realy tough
Not that tough! It was a great teaser I thought, keep it up
I thought it was really tough, but fun to attempt
How can I say this without being unkind? No, no, no, no, no. Good heavens, no! This teaser has more holes than a half-pound of swiss cheese. Do you want avoid fractions? Do you wish avoid negative numbers? Say so. While fractions would be silly, penalties are quite common. To minimize the possibilities, I hazard to assume the solutions are limited to natural numbers.
There are six variables, but without the hint there are at most four independent statements. This makes a single answer impossible. (Other point schemes include 53,84,45,22,128,12 | 25,78,39,64,52,10 | 49,84,45,28,118,10. These three only scratch the surface.)
Shame on you for hiding CRUCIAL info in the hint. While the data there narrows the possibilities, they are still myriad, e.g. 49,81,42,28,115,16.
I LOVE the premise, but the execution stinks.
There are six variables, but without the hint there are at most four independent statements. This makes a single answer impossible. (Other point schemes include 53,84,45,22,128,12 | 25,78,39,64,52,10 | 49,84,45,28,118,10. These three only scratch the surface.)
Shame on you for hiding CRUCIAL info in the hint. While the data there narrows the possibilities, they are still myriad, e.g. 49,81,42,28,115,16.
I LOVE the premise, but the execution stinks.
Hmm. I see Stil has found other solutions, so my method of solving must have been partially based on intuition rather than proven fact.
After taking the difference of each set of equations I determined that 1) all the values were different and 2) that the difference between any two values was a multiple of 13. Taking this information with the totals I determined that the values were 1, 2, 3, 4, 5, & 6 plugged into 13v - 1. Then I reduced the problem by logical exclusion without any trial and error.
So I agree with Stil: great idea, poor execution.
After taking the difference of each set of equations I determined that 1) all the values were different and 2) that the difference between any two values was a multiple of 13. Taking this information with the totals I determined that the values were 1, 2, 3, 4, 5, & 6 plugged into 13v - 1. Then I reduced the problem by logical exclusion without any trial and error.
So I agree with Stil: great idea, poor execution.
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